Question 1
How far does it travel?
A train runs at a steady 72 km/h for 4 hours.
- 288
- 72
- 283
- 76
- 18
Show the worked solution
- Distance = speed × time = 72 × 4 = 288 km.
- Answer: 288 km.
Speed distance and time questions are three-quarters unit discipline. Most wrong answers on this family are correct arithmetic on a kilometre-per-hour figure that should have been metres per second. Each walkthrough below converts first and computes second, and states the conversion it used rather than assuming it.
Download the PDF — 15 questions with answers
Free, ungated, no email. This is the speed distance time questions with answers PDF — the same 15 questions as below, with every worked solution at the back, ready to print.
The 15 questions below are ordered the way an exam block is rather than easiest-first: two gentle openers, then a run of medium, and a hard one every sixth question — 2 of the 15 sit in the hard band. Every question is a time, speed & distance.
Work each question on paper before you open its solution. The walkthrough is the method itself, step for step, so reading it first turns a practice set into a reading exercise and teaches nothing. If you are stuck on the method rather than on one question, the method guide is a better place to start than the next question: Speed, distance and time: units first.
Every question below was generated by the same engine that mints the ComputePrep daily timed drill, and machine-checked before it reached this page — a multiple-choice question validates its own answer against its own options at generation, and ships only with a walkthrough attached. The walkthrough is the engine's own.
How far does it travel?
A train runs at a steady 72 km/h for 4 hours.
How far does it travel?
A train runs at a steady 30 km/h for 5 hours.
How long does the journey take?
A train covers 640 km at a steady 80 km/h.
How far does it travel?
A train runs at a steady 30 km/h for 8 hours.
How far does it travel?
A train runs at a steady 30 km/h for 5 hours.
What is its average speed for the whole journey?
A car covers a certain distance at 20 km/h and returns along the same route at 60 km/h.
How long does the journey take?
A train covers 280 km at a steady 40 km/h.
How long does the journey take?
A train covers 360 km at a steady 40 km/h.
What is its average speed for the whole journey?
A car covers a certain distance at 10 km/h and returns along the same route at 40 km/h.
How long does the journey take?
A train covers 80 km at a steady 40 km/h.
How long does the journey take?
A train covers 90 km at a steady 30 km/h.
What is its average speed for the whole journey?
A car covers a certain distance at 20 km/h and returns along the same route at 60 km/h.
How long does the journey take?
A train covers 216 km at a steady 72 km/h.
How far does it travel?
A train runs at a steady 30 km/h for 9 hours.
How far does it travel?
A train runs at a steady 50 km/h for 5 hours.
Most free practice for this topic is a scanned upload or a blog quiz, and neither can tell you a question has exactly one answer. That is the one thing this set can promise: it is minted, not typed. The engine behind it serves ComputePrep's daily timed drill, so the questions here are the same shape as the ones a live round would give you — and there is an unlimited supply of them, which is why this page can be regenerated rather than padded.
If you want the method rather than more questions, Speed, distance and time: units first covers the approach, the traps and a worked table. This page and that one deliberately answer different questions: that one is how do I solve these, this one is give me speed distance and time questions with the answers.
Multiply by 5/18 to go from km/h to m/s, and by 18/5 to go back. Any question involving a train passing a pole, a platform or another train needs metres per second, and doing that conversion before anything else removes the most common error in the family.
Add the speeds when they move towards each other or in opposite directions; subtract when they move the same way. The distance covered is the sum of both lengths when one train passes another, and just the train's own length when it passes a pole.
Not the average of the two speeds — it is the harmonic mean, 2ab/(a + b), because equal distances take unequal times. At 40 and 60 km/h the average is 48, not 50. The arithmetic mean is always among the options, so the distinction is worth holding firmly.
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