Antyayordashake
Multiply two numbers whose units add to 10 — one step, no working
To multiply two numbers whose units add to 10 and that share the same tens digit, multiply the tens digit by one more than itself for the front, and multiply the two units digits for the back. For 43 × 47: 4 × 5 = 20 and 3 × 7 = 21, giving 2021. It is the fastest pattern in the whole Vedic set.
This is the narrowest of the Vedic techniques and the most satisfying when it lands: a multiplication that looks like real work resolves in about two seconds. It is a close relative of the squaring rule for numbers ending in 5, which is simply this pattern with both units equal to 5.
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How to multiply two numbers whose units add to 10
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Check both conditions before using it
The tens parts must be identical and the units must sum to exactly ten. 43 and 47 qualify; 43 and 57 do not. Checking takes a moment and stops the method being applied where it produces a wrong answer.
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Multiply the leading part by one more than itself
For 43 × 47, the leading part is 4, so compute 4 × 5 = 20. This is the front of the answer, and it is the same Ekadhikena step used for squaring numbers that end in 5.
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Multiply the two units digits for the back
3 × 7 = 21. Pad to two digits — 62 × 68 gives 42 and 16, that is 4216, and 61 × 69 gives 42 and 09, that is 4209. The pad is where the errors live.
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Recognise squaring as the special case
When both units are 5, the two numbers are equal and the rule becomes the squaring shortcut: 75 × 75 is 7 × 8 = 56 then 5 × 5 = 25, giving 5625. One pattern, two uses.
Does the pattern apply?
| Pair | Applies? |
| 43 × 47 | Yes — same tens, units 3 + 7 = 10 |
| 62 × 68 | Yes — 2 + 8 = 10 |
| 75 × 75 | Yes — the squaring special case |
| 43 × 57 | No — different tens digits |
| 44 × 47 | No — units sum to 11 |
| 105 × 105 | Yes — leading part 10, units both 5 |
3 real multiply two numbers whose units add to 10, with worked solutions
Generated by the same engine that mints the ComputePrep daily. Each answer is computed
from the numbers printed in the question, and the walkthrough below each one is the engine's own working
— not a solution written afterwards. Reload this page's live drill and you get different numbers.
Question 1
73 × 77 = ?
Units sum to 10, same lead — beat the clock.
- 4921
- 5613
- 5621
- 5631
- 5610
Show the worked solution
- Units 3 + 7 = 10 with the same lead 7 — Antyayordashake applies.
- Left: 7 × 8 = 56. Right: 3 × 7 = 21 (always two digits).
- 56 | 21 → 5621.
- Answer: 5621.
Question 2
81 × 89 = ?
Units sum to 10, same lead — beat the clock.
- 7214
- 6409
- 7209
- 7210
- 729
Show the worked solution
- Units 1 + 9 = 10 with the same lead 8 — Antyayordashake applies.
- Left: 8 × 9 = 72. Right: 1 × 9 = 09 (always two digits).
- 72 | 09 → 7209.
- Answer: 7209.
Question 3
37 × 33 = ?
Units sum to 10, same lead — beat the clock.
- 1221
- 1210
- 921
- 1209
- 1231
Show the worked solution
- Units 7 + 3 = 10 with the same lead 3 — Antyayordashake applies.
- Left: 3 × 4 = 12. Right: 7 × 3 = 21 (always two digits).
- 12 | 21 → 1221.
- Answer: 1221.
Common mistakes this drill is built from
The wrong options are not random numbers. Each one is the result of a specific careless error for this
topic, so picking one tells you which habit is costing you marks.
Applying it when the tens digits differ
Both conditions are required. 43 × 57 looks similar and the method gives a confidently wrong answer, because nothing in the arithmetic signals that it does not apply.
Not padding the back to two digits
61 × 69 gives a back part of 9, which must be written 09. Dropping the pad shifts the answer by a factor of ten.
Spending time checking on numbers that obviously do not fit
The check should take under a second. If it does not resolve immediately, use crosswise multiplication and move on.
FAQ
When can I use this multiplication shortcut?
Only when the two numbers share the same leading part and their units digits add to exactly ten — 43 × 47, 62 × 68, 105 × 105. Both conditions must hold. If either fails, the crosswise method is the right choice.
How is this related to squaring numbers ending in 5?
It is the same rule. A number ending in 5 multiplied by itself has an identical leading part and units summing to ten, so 75 × 75 gives 7 × 8 = 56 and 5 × 5 = 25, or 5625. Learning one gives you the other for free.
Does it work for three-digit numbers?
Yes. The leading part can be any length, so 112 × 118 gives 11 × 12 = 132 and 2 × 8 = 16, that is 13216. The units must still sum to ten and everything before them must match.
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