Time and work questions with answers
Time and work questions are fastest when the job is a whole number of units rather than 1. Take the LCM of the given days, give each worker a rate in units per day, and the fractions disappear. Every walkthrough below does exactly that, which is why none of them contains a common denominator.
How to use this set
The 15 questions below are ordered the way an exam block is rather than easiest-first: two gentle openers, then a run of medium, and a hard one every sixth question — 2 of the 15 sit in the hard band. Every question is a time & work.
Work each question on paper before you open its solution. The walkthrough is the method itself, step for step, so reading it first turns a practice set into a reading exercise and teaches nothing. If you are stuck on the method rather than on one question, the method guide is a better place to start than the next question: Time and work: the LCM unit method.
15 time and work questions with answers
Every question below was generated by the same engine that mints the ComputePrep daily timed drill, and machine-checked before it reached this page — a multiple-choice question validates its own answer against its own options at generation, and ships only with a walkthrough attached. The walkthrough is the engine's own.
Question 1
In how many hours will the tank be full?
An inlet pipe fills a tank in 20 hours; an outlet pipe empties the full tank in 30 hours.
Both pipes are opened together on an empty tank.
- 69
- 12
- 60
- 50
- 65
Show the worked solution
- Take the tank as 60 units, so the inlet adds 3/hour and the outlet removes 2/hour.
- Net inflow = 3 − 2 = 1 units/hour — an outlet SUBTRACTS.
- Time = 60 ÷ 1 = 60 hours.
- Answer: 60 hours.
Question 2
In how many hours will the tank be full?
An inlet pipe fills a tank in 20 hours; an outlet pipe empties the full tank in 30 hours.
Both pipes are opened together on an empty tank.
- 12
- 60
- 67
- 74
- 70
Show the worked solution
- Take the tank as 60 units, so the inlet adds 3/hour and the outlet removes 2/hour.
- Net inflow = 3 − 2 = 1 units/hour — an outlet SUBTRACTS.
- Time = 60 ÷ 1 = 60 hours.
- Answer: 60 hours.
Question 3
In how many hours will the tank be full?
An inlet pipe fills a tank in 15 hours; an outlet pipe empties the full tank in 30 hours.
Both pipes are opened together on an empty tank.
- 21
- 30
- 15
- 10
- 22
Show the worked solution
- Take the tank as 30 units, so the inlet adds 2/hour and the outlet removes 1/hour.
- Net inflow = 2 − 1 = 1 units/hour — an outlet SUBTRACTS.
- Time = 30 ÷ 1 = 30 hours.
- Answer: 30 hours.
Question 4
Working together, in how many days will Deepak and Latha finish it?
Deepak is 2 times as efficient as Latha.
Latha alone can finish the work in 12 days.
- 6
- 2
- 4
- 3
- 24
Show the worked solution
- 2× the efficiency means 2× the work per day, so Deepak needs 12 ÷ 2 = 6 days alone.
- Per day: Latha does 1/12, Deepak does 1/6 — together 3/12 of the job.
- So the job takes 12 ÷ 3 = 4 days.
- Answer: 4 days.
Question 5
Working together, in how many days will they finish it?
Faiz can complete a piece of work in 10 days.
Nandini can complete the same work in 15 days.
- 13
- 10
- 25
- 5
- 6
Show the worked solution
- Take the total work as 30 units (the LCM of 10 and 15).
- Faiz does 3 units/day, Nandini does 2 units/day — add the RATES, never the days.
- Together they do 5 units/day, so the job takes 30 ÷ 5 = 6 days.
- Answer: 6 days.
Question 6
In how many days will Meera finish the remaining work?
Karan can finish a job in 8 days and Meera can finish it in 24 days.
Karan works alone for 3 days, then leaves.
- 15
- 6
- 5
- 22
- 24
Show the worked solution
- Take the total work as 24 units, so Karan does 3/day and Meera does 1/day.
- Karan completes 3 × 3 = 9 units, leaving 24 − 9 = 15 units.
- Meera needs 15 ÷ 1 = 15 days.
- Answer: 15 days.
Question 7
Working together, in how many days will they finish it?
Anil can complete a piece of work in 16 days.
Bhavna can complete the same work in 48 days.
- 32
- 11
- 10
- 12
- 64
Show the worked solution
- Take the total work as 48 units (the LCM of 16 and 48).
- Anil does 3 units/day, Bhavna does 1 units/day — add the RATES, never the days.
- Together they do 4 units/day, so the job takes 48 ÷ 4 = 12 days.
- Answer: 12 days.
Question 8
In how many hours will the tank be full?
An inlet pipe fills a tank in 20 hours; an outlet pipe empties the full tank in 30 hours.
Both pipes are opened together on an empty tank.
- 50
- 60
- 75
- 12
- 72
Show the worked solution
- Take the tank as 60 units, so the inlet adds 3/hour and the outlet removes 2/hour.
- Net inflow = 3 − 2 = 1 units/hour — an outlet SUBTRACTS.
- Time = 60 ÷ 1 = 60 hours.
- Answer: 60 hours.
Question 9
Working together, in how many days will they finish it?
Faiz can complete a piece of work in 14 days.
Nandini can complete the same work in 35 days.
- 40
- 25
- 10
- 4
- 49
Show the worked solution
- Take the total work as 70 units (the LCM of 14 and 35).
- Faiz does 5 units/day, Nandini does 2 units/day — add the RATES, never the days.
- Together they do 7 units/day, so the job takes 70 ÷ 7 = 10 days.
- Answer: 10 days.
Question 10
Working together, in how many days will they finish it?
Anil can complete a piece of work in 18 days.
Bhavna can complete the same work in 9 days.
- 6
- 1
- 27
- 14
- 0
Show the worked solution
- Take the total work as 18 units (the LCM of 18 and 9).
- Anil does 1 units/day, Bhavna does 2 units/day — add the RATES, never the days.
- Together they do 3 units/day, so the job takes 18 ÷ 3 = 6 days.
- Answer: 6 days.
Question 11
Working together, in how many days will they finish it?
Faiz can complete a piece of work in 12 days.
Nandini can complete the same work in 36 days.
- 9
- 48
- 12
- 24
- 4
Show the worked solution
- Take the total work as 36 units (the LCM of 12 and 36).
- Faiz does 3 units/day, Nandini does 1 units/day — add the RATES, never the days.
- Together they do 4 units/day, so the job takes 36 ÷ 4 = 9 days.
- Answer: 9 days.
Question 12
In how many days will Latha finish the remaining work?
Deepak can finish a job in 9 days and Latha can finish it in 18 days.
Deepak works alone for 4 days, then leaves.
- 40
- 18
- 6
- 5
- 10
Show the worked solution
- Take the total work as 18 units, so Deepak does 2/day and Latha does 1/day.
- Deepak completes 2 × 4 = 8 units, leaving 18 − 8 = 10 units.
- Latha needs 10 ÷ 1 = 10 days.
- Answer: 10 days.
Question 13
Working together, in how many days will they finish it?
Karan can complete a piece of work in 20 days.
Meera can complete the same work in 5 days.
- 3
- 1
- 4
- 25
- 0
Show the worked solution
- Take the total work as 20 units (the LCM of 20 and 5).
- Karan does 1 units/day, Meera does 4 units/day — add the RATES, never the days.
- Together they do 5 units/day, so the job takes 20 ÷ 5 = 4 days.
- Answer: 4 days.
Question 14
Working together, in how many days will they finish it?
Karan can complete a piece of work in 9 days.
Meera can complete the same work in 18 days.
- 4
- 6
- 9
- 14
- 27
Show the worked solution
- Take the total work as 18 units (the LCM of 9 and 18).
- Karan does 2 units/day, Meera does 1 units/day — add the RATES, never the days.
- Together they do 3 units/day, so the job takes 18 ÷ 3 = 6 days.
- Answer: 6 days.
Question 15
Working together, in how many days will they finish it?
Ravi can complete a piece of work in 10 days.
Sunita can complete the same work in 15 days.
- 25
- 13
- 5
- 3
- 6
Show the worked solution
- Take the total work as 30 units (the LCM of 10 and 15).
- Ravi does 3 units/day, Sunita does 2 units/day — add the RATES, never the days.
- Together they do 5 units/day, so the job takes 30 ÷ 5 = 6 days.
- Answer: 6 days.
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Where these questions come from
Most free practice for this topic is a scanned upload or a blog quiz, and neither can tell you a question has exactly one answer. That is the one thing this set can promise: it is minted, not typed. The engine behind it serves ComputePrep's daily timed drill, so the questions here are the same shape as the ones a live round would give you — and there is an unlimited supply of them, which is why this page can be regenerated rather than padded.
If you want the method rather than more questions, Time and work: the LCM unit method covers the approach, the traps and a worked table. This page and that one deliberately answer different questions: that one is how do I solve these, this one is give me time and work questions with the answers.
FAQ
Why use the LCM method instead of fractions?
Because it removes every fraction from the problem. If A takes 12 days and B takes 18, set the job at 36 units: A does 3 a day, B does 2, together 5. The answer is 36/5 days, reached without ever adding 1/12 and 1/18 — and without the arithmetic slip that usually causes.
How do I handle efficiency ratios?
Efficiency and time are inversely proportional. If A is twice as efficient as B, A takes half as long. Convert an efficiency ratio into a time ratio before doing anything else; carrying an efficiency ratio into a time formula is the standard way this family goes wrong.
Are pipes and cisterns the same as time and work?
Identical, with one addition: an outlet pipe has a negative rate. Set the tank at the LCM of the fill times, add the inlet rates, subtract the outlet rates, and divide. If the net rate is negative the tank never fills, and that is sometimes the intended answer.
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