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Simple and compound interest questions with answers

These simple and compound interest questions cover the two-year difference type, the equal-instalment type and the plain rate-and-time type that banking papers set every session. Each walkthrough works compound interest as successive percentage multipliers, which is faster than the formula and much harder to misapply under time pressure.

Download the PDF — 15 questions with answers

Free, ungated, no email. This is the simple and compound interest questions with answers PDF — the same 15 questions as below, with every worked solution at the back, ready to print.

How to use this set

The 15 questions below are ordered the way an exam block is rather than easiest-first: two gentle openers, then a run of medium, and a hard one every sixth question — 2 of the 15 sit in the hard band. Every question is a simple & compound interest.

Work each question on paper before you open its solution. The walkthrough is the method itself, step for step, so reading it first turns a practice set into a reading exercise and teaches nothing. If you are stuck on the method rather than on one question, the method guide is a better place to start than the next question: Interest: simple, compound and the difference.

15 simple and compound interest questions with answers

Every question below was generated by the same engine that mints the ComputePrep daily timed drill, and machine-checked before it reached this page — a multiple-choice question validates its own answer against its own options at generation, and ships only with a walkthrough attached. The walkthrough is the engine's own.

Question 1

What is the simple interest earned?

₹120000 is deposited for 2 years at 10% per annum, simple interest.

  1. 24000
  2. 144000
  3. 24012
  4. 12000
  5. 25200
Show the worked solution
  1. Simple interest = P × R × T ÷ 100 = ₹120000 × 10 × 2 ÷ 100 = ₹24000.
  2. Each year earns the same ₹12000 under simple interest.
  3. Answer: 24000.

Question 2

What is the simple interest earned?

₹30000 is deposited for 2 years at 10% per annum, simple interest.

  1. 3000
  2. 36000
  3. 6300
  4. 6000
  5. 5992
Show the worked solution
  1. Simple interest = P × R × T ÷ 100 = ₹30000 × 10 × 2 ÷ 100 = ₹6000.
  2. Each year earns the same ₹3000 under simple interest.
  3. Answer: 6000.

Question 3

By how much does the compound interest exceed the simple interest?

A sum of ₹60000 is invested for 2 years at 10% per annum.

  1. 587
  2. 1200
  3. 12000
  4. 600
  5. 12600
Show the worked solution
  1. Simple interest = ₹60000 × 10 × 2 ÷ 100 = ₹12000.
  2. Compound interest = ₹60000 × [(1 + 10/100)² − 1] = ₹12600.
  3. Difference = ₹12600 − ₹12000 = ₹600. (Shortcut: P × (R/100)² gives the same.)
  4. Answer: 600.

Question 4

What is the simple interest earned?

₹50000 is deposited for 2 years at 25% per annum, simple interest.

  1. 12500
  2. 25000
  3. 75000
  4. 28125
  5. 25004
Show the worked solution
  1. Simple interest = P × R × T ÷ 100 = ₹50000 × 25 × 2 ÷ 100 = ₹25000.
  2. Each year earns the same ₹12500 under simple interest.
  3. Answer: 25000.

Question 5

What is the simple interest earned?

₹10000 is deposited for 2 years at 25% per annum, simple interest.

  1. 2500
  2. 5000
  3. 15000
  4. 5011
  5. 5625
Show the worked solution
  1. Simple interest = P × R × T ÷ 100 = ₹10000 × 25 × 2 ÷ 100 = ₹5000.
  2. Each year earns the same ₹2500 under simple interest.
  3. Answer: 5000.

Question 6

What is the compound interest earned?

₹60000 is deposited for 2 years at 5% per annum, compounded annually.

  1. 6000
  2. 150
  3. 3000
  4. 6144
  5. 6150
Show the worked solution
  1. Amount = ₹60000 × (1 + 5/100)² = ₹66150.
  2. Compound interest = amount − principal = ₹66150 − ₹60000 = ₹6150 — interest is the gain, not the amount.
  3. Answer: 6150.

Question 7

What is the simple interest earned?

₹90000 is deposited for 2 years at 25% per annum, simple interest.

  1. 44988
  2. 45000
  3. 44998
  4. 22500
  5. 50625
Show the worked solution
  1. Simple interest = P × R × T ÷ 100 = ₹90000 × 25 × 2 ÷ 100 = ₹45000.
  2. Each year earns the same ₹22500 under simple interest.
  3. Answer: 45000.

Question 8

What is the simple interest earned?

₹20000 is deposited for 2 years at 25% per annum, simple interest.

  1. 11250
  2. 5000
  3. 10000
  4. 10009
  5. 30000
Show the worked solution
  1. Simple interest = P × R × T ÷ 100 = ₹20000 × 25 × 2 ÷ 100 = ₹10000.
  2. Each year earns the same ₹5000 under simple interest.
  3. Answer: 10000.

Question 9

By how much does the compound interest exceed the simple interest?

A sum of ₹20000 is invested for 2 years at 20% per annum.

  1. 793
  2. 800
  3. 200
  4. 8000
  5. 8800
Show the worked solution
  1. Simple interest = ₹20000 × 20 × 2 ÷ 100 = ₹8000.
  2. Compound interest = ₹20000 × [(1 + 20/100)² − 1] = ₹8800.
  3. Difference = ₹8800 − ₹8000 = ₹800. (Shortcut: P × (R/100)² gives the same.)
  4. Answer: 800.

Question 10

By how much does the compound interest exceed the simple interest?

A sum of ₹10000 is invested for 2 years at 10% per annum.

  1. 95
  2. 100
  3. 2100
  4. 2000
  5. 99
Show the worked solution
  1. Simple interest = ₹10000 × 10 × 2 ÷ 100 = ₹2000.
  2. Compound interest = ₹10000 × [(1 + 10/100)² − 1] = ₹2100.
  3. Difference = ₹2100 − ₹2000 = ₹100. (Shortcut: P × (R/100)² gives the same.)
  4. Answer: 100.

Question 11

By how much does the compound interest exceed the simple interest?

A sum of ₹90000 is invested for 2 years at 5% per annum.

  1. 9000
  2. 219
  3. 224
  4. 225
  5. 9225
Show the worked solution
  1. Simple interest = ₹90000 × 5 × 2 ÷ 100 = ₹9000.
  2. Compound interest = ₹90000 × [(1 + 5/100)² − 1] = ₹9225.
  3. Difference = ₹9225 − ₹9000 = ₹225. (Shortcut: P × (R/100)² gives the same.)
  4. Answer: 225.

Question 12

By how much does the compound interest exceed the simple interest?

A sum of ₹40000 is invested for 2 years at 25% per annum.

  1. 22500
  2. 20000
  3. 2500
  4. 5000
  5. 2511
Show the worked solution
  1. Simple interest = ₹40000 × 25 × 2 ÷ 100 = ₹20000.
  2. Compound interest = ₹40000 × [(1 + 25/100)² − 1] = ₹22500.
  3. Difference = ₹22500 − ₹20000 = ₹2500. (Shortcut: P × (R/100)² gives the same.)
  4. Answer: 2500.

Question 13

What is the simple interest earned?

₹40000 is deposited for 2 years at 20% per annum, simple interest.

  1. 15990
  2. 16000
  3. 17600
  4. 15993
  5. 8000
Show the worked solution
  1. Simple interest = P × R × T ÷ 100 = ₹40000 × 20 × 2 ÷ 100 = ₹16000.
  2. Each year earns the same ₹8000 under simple interest.
  3. Answer: 16000.

Question 14

What is the simple interest earned?

₹120000 is deposited for 2 years at 5% per annum, simple interest.

  1. 6000
  2. 12300
  3. 11988
  4. 12000
  5. 132000
Show the worked solution
  1. Simple interest = P × R × T ÷ 100 = ₹120000 × 5 × 2 ÷ 100 = ₹12000.
  2. Each year earns the same ₹6000 under simple interest.
  3. Answer: 12000.

Question 15

What is the simple interest earned?

₹100000 is deposited for 2 years at 5% per annum, simple interest.

  1. 110000
  2. 10250
  3. 5000
  4. 10000
  5. 10006
Show the worked solution
  1. Simple interest = P × R × T ÷ 100 = ₹100000 × 5 × 2 ÷ 100 = ₹10000.
  2. Each year earns the same ₹5000 under simple interest.
  3. Answer: 10000.
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Where these questions come from

Most free practice for this topic is a scanned upload or a blog quiz, and neither can tell you a question has exactly one answer. That is the one thing this set can promise: it is minted, not typed. The engine behind it serves ComputePrep's daily timed drill, so the questions here are the same shape as the ones a live round would give you — and there is an unlimited supply of them, which is why this page can be regenerated rather than padded.

If you want the method rather than more questions, Interest: simple, compound and the difference covers the approach, the traps and a worked table. This page and that one deliberately answer different questions: that one is how do I solve these, this one is give me simple and compound interest questions with the answers.

FAQ

What is the shortcut for the two-year SI and CI difference?

The difference over two years equals principal times rate squared over ten thousand. For three years it is principal times rate squared times (300 + rate) over one million. The two-year version alone answers a large share of the interest questions on a bank paper.

How do I handle half-yearly compounding?

Halve the rate and double the number of periods, then apply the multiplier that many times. Ten per cent per annum compounded half-yearly is five per cent applied twice a year, which gives 10.25 per cent effective — and that quarter point is exactly what the distractor options are built around.

When is simple interest larger than compound interest?

Never after the first period, and equal during it. For any whole number of periods beyond one, compound exceeds simple, and the gap widens with both rate and time. An option showing compound below simple over two years can be eliminated without any calculation.

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