Exam path · Time & Work
Time and work questions, solved by rates not by guessing
Time and work questions give you how long each person takes alone and ask how long they take together, or the reverse. They are solved by adding rates, never by adding or averaging days. Take the total job as the LCM of the given days, convert each worker into units per day, add those, and divide — which turns the whole topic into one subtraction and one division.
Time and work is typically one or two questions in a banking prelims paper and appears in almost every SSC and railway paper too. It has a reputation for being slow, and it earns that reputation only when it is attacked with equations. The LCM-units method below turns the standard question into two lines of mental arithmetic, and the pipes-and-cisterns questions are the same method with one rate made negative.
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How to solve time and work questions with the LCM method
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Make the total work the LCM of the given days
If Ravi takes 6 days and Sunita 12, call the whole job 12 units. There are no fractions after this step, which is the entire point — the fractions are what make this topic feel slow.
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Convert each person into units per day
Ravi does 12 ÷ 6 = 2 units a day, Sunita 12 ÷ 12 = 1. These are rates, and rates are the only thing in this topic you are allowed to add.
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Add the rates, then divide the work by the total
Together they do 3 units a day, so the job takes 12 ÷ 3 = 4 days. Notice that 4 is less than either person alone — a two-person job is always faster than the faster worker, and that check alone eliminates two options.
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For pipes and leaks, make the outflow negative
A leak that empties the tank in 20 hours is a rate of −(work/20). Everything else is unchanged: add the rates, divide, done. A question with a leak is not a new topic, it is a minus sign.
The same question in three disguises
| What the paper says | What it means |
| A alone: 10 days, B alone: 15 days | Rates 3 and 2 out of 30 units — together 5, so 6 days |
| A is twice as efficient as B | Rate of A = 2 × rate of B; days are in the ratio 1:2, not 2:1 |
| A and B together: 6 days, A alone: 10 | B's rate = total − A's = the subtraction that answers most of these |
| A pipe fills in 4 h, a leak empties in 12 h | Rates +3 and −1 out of 12 units — net 2, so 6 hours |
3 real time and work questions, with worked solutions
Generated by the same engine that mints the ComputePrep daily. Each answer is computed
from the numbers printed in the question, and the walkthrough below each one is the engine's own working
— not a solution written afterwards. Reload this page's live drill and you get different numbers.
Question 1
Karan can complete a piece of work in 12 days.
Meera can complete the same work in 36 days.
Working together, in how many days will they finish it?
- 6
- 5
- 3
- 9
- 48
Show the worked solution
- Take the total work as 36 units (the LCM of 12 and 36).
- Karan does 3 units/day, Meera does 1 units/day — add the RATES, never the days.
- Together they do 4 units/day, so the job takes 36 ÷ 4 = 9 days.
- Answer: 9 days.
Question 2
An inlet pipe fills a tank in 20 hours; an outlet pipe empties the full tank in 30 hours.
Both pipes are opened together on an empty tank.
In how many hours will the tank be full?
- 74
- 70
- 60
- 12
- 68
Show the worked solution
- Take the tank as 60 units, so the inlet adds 3/hour and the outlet removes 2/hour.
- Net inflow = 3 − 2 = 1 units/hour — an outlet SUBTRACTS.
- Time = 60 ÷ 1 = 60 hours.
- Answer: 60 hours.
Question 3
Karan can complete a piece of work in 14 days.
Meera can complete the same work in 35 days.
Working together, in how many days will they finish it?
- 49
- 10
- 25
- 50
- 4
Show the worked solution
- Take the total work as 70 units (the LCM of 14 and 35).
- Karan does 5 units/day, Meera does 2 units/day — add the RATES, never the days.
- Together they do 7 units/day, so the job takes 70 ÷ 7 = 10 days.
- Answer: 10 days.
Common mistakes this drill is built from
The wrong options are not random numbers. Each one is the result of a specific careless error for this
topic, so picking one tells you which habit is costing you marks.
Adding or averaging the days
If A takes 6 days and B takes 12, together they do not take 18 days or 9. Days are not additive; rates are. Both 18 and 9 will be sitting in the options because the setter knows exactly which mistake you are about to make.
Inverting efficiency and time
"A is twice as efficient as B" means A takes half as long, not twice as long. The sentence and the arithmetic point in opposite directions, and under a clock that is enough.
Forgetting that the answer must beat the faster worker
Any combined-work answer has to be smaller than the smallest individual time. If yours is not, you added days somewhere. This check costs a second and catches the majority of errors in this topic.
Why your answer came out wrong
The specific wrong numbers this topic produces, and what each one tells you about the step
you took. If you have just got a question wrong and want to know which habit did it, start here.
A finishes in 12 days and B in 18 — why is the answer not 15 days?
You cannot average days, only rates. Together they do 1/12 + 1/18 = 5/36 of the job a day, so they need 36/5 = 7.2 days. The answer must always be smaller than 12, the faster worker's own time, and 15 fails that check before you calculate anything.
Why is my answer longer than one worker takes alone?
You added times where you should have added rates. Two people working together always finish faster than the quicker of them working alone, so any answer above the smaller individual time is wrong on sight. Redo it in LCM units: for 12 and 18 days, call the job 36 units, A does 3 a day, B does 2.
A is twice as efficient as B — does A take twice as long?
The opposite: efficiency and time are inverses. If A is twice as efficient, A takes half the time. With B at 30 days, A is 15 and together they finish in 10. Writing efficiency as 2 : 1 and time as 1 : 2 side by side in the margin stops the inversion.
FAQ
What is the fastest method for time and work questions?
The LCM method. Take the total work as the LCM of the given days, convert each worker into units per day, add the rates and divide the total work by the sum. It removes every fraction from the calculation and works unchanged for pipes and cisterns.
How long should a time and work question take in prelims?
Between 45 and 70 seconds. This drill enforces exactly that: 45 seconds on easy, 55 on medium and 70 on hard, timed on the server rather than in your browser.
Are pipes and cisterns the same topic?
Yes, mathematically. A filling pipe is a positive rate and a leak or outlet is a negative one. Add the rates the same way and divide the same way; nothing else changes.
Do I need to memorise formulas for time and work?
No. The combined-time formula xy divided by x plus y is just the LCM method written out, and it only covers the two-worker case. Learning the rate method once covers every variant, including efficiency ratios, partial work and leaks.
Is this practice free?
Yes, free with no account and no app-store download. It runs in your browser and installs as a mobile app if you want it to.
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