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Vedic maths tricks questions with answers

These vedic maths tricks questions run through the seven techniques a bank paper can actually be beaten with — squaring, complementary products, difference of squares, Nikhilam, crosswise multiplication, Paravartya division and proportional multiplication — two questions each. Every walkthrough is the fast method, step for step, not the long multiplication with a label on it.

Download the PDF — 14 questions with answers

Free, ungated, no email. This is the vedic maths tricks with answers PDF — the same 14 questions as below, with every worked solution at the back, ready to print.

How to use this set

The 14 questions below are ordered the way an exam block is rather than easiest-first: two gentle openers, then a run of medium, and a hard one every sixth question — 2 of the 14 sit in the hard band. The set mixes vedic squaring, complementary products, difference of squares, nikhilam, crosswise multiplication, paravartya division and anurupyena multiplication, in the round-robin the paper itself sets rather than one form at a time.

Work each question on paper before you open its solution. The walkthrough is the method itself, step for step, so reading it first turns a practice set into a reading exercise and teaches nothing. If you are stuck on the method rather than on one question, the method guide is a better place to start than the next question: Vedic multiplication: the crosswise sweep.

14 vedic maths tricks questions with answers

Every question below was generated by the same engine that mints the ComputePrep daily timed drill, and machine-checked before it reached this page — a multiple-choice question validates its own answer against its own options at generation, and ships only with a walkthrough attached. The walkthrough is the engine's own.

Question 1

Squaring a number ending in 5 — beat the clock.

95² = ?

  1. 9039
  2. 8125
  3. 9025
  4. 10025
  5. 9055
Show the worked solution
  1. Ends in 5 — Ekadhikena: take 9, multiply by one more: 9 × 10 = 90.
  2. Append 25: 90 | 25 → 9025.
  3. Answer: 9025.

Question 2

Units sum to 10, same lead — beat the clock.

73 × 77 = ?

  1. 4921
  2. 5636
  3. 5621
  4. 5628
  5. 5631
Show the worked solution
  1. Units 3 + 7 = 10 with the same lead 7 — Antyayordashake applies.
  2. Left: 7 × 8 = 56. Right: 3 × 7 = 21 (always two digits).
  3. 56 | 21 → 5621.
  4. Answer: 5621.

Question 3

Multiply via the midpoint — beat the clock.

51 × 69 = ?

  1. 2601
  2. 3513
  3. 3519
  4. 3499
  5. 3681
Show the worked solution
  1. 51 and 69 straddle 60 by 9 — Sankalana: a × b = m² − d².
  2. 60² − 9² = 3600 − 81 = 3519.
  3. Answer: 3519.

Question 4

Nikhilam multiplication — beat the clock.

1025 × 1008 = ?

  1. 2033000
  2. 1033200
  3. 1033207
  4. 1026008
  5. 1033206
Show the worked solution
  1. Choose the base (nearest power of 10): 1000.
  2. Distance from base: 1025 is 25 above 1000, 1008 is 8 above 1000.
  3. Cross-add: 1025 + 8 = 1033 (same as 1008 + 25).
  4. Multiply the distances: 25 × 8 = 200.
  5. Base 1000 has 3 zeros, so the right-hand part must occupy exactly 3 digits.
  6. 200 fits, padded to 3 digits → 200.
  7. Left part: 1033. Right part: 200.
  8. Write them side by side: 1033 | 200 = 1033200.

Question 5

Crosswise multiplication — beat the clock.

18 × 43 = ?

  1. 774
  2. 786
  3. 775
  4. 776
  5. 454
Show the worked solution
  1. Units: 8 × 3 = 24.
  2. Cross: 1×3 + 8×4 = 35; tens: 1 × 4 = 4 — stack with carries.
  3. 400 + 350 + 24 = 774.
  4. Answer: 774.

Question 6

Dividing by 11 — beat the clock.

69549 ÷ 11 — what is the QUOTIENT?

  1. 6954
  2. 6322
  3. 6504
  4. 63227
  5. 6292
Show the worked solution
  1. 69549 ÷ 11 — Paravartya: 11 = 10 + 1, so the flag digit is 1; negate it to −1.
  2. Bring down the first digit as-is: 6 (first quotient digit).
  3. 9 + (−1 × 6) = 3 (next quotient digit).
  4. 5 + (−1 × 3) = 2 (next quotient digit).
  5. 4 + (−1 × 2) = 2 (next quotient digit).
  6. Last digit gives the remainder the same way: 9 + (−1 × 2) = 7.
  7. Quotient 6322, remainder 7 — check: 6322 × 11 + 7 = 69549.
  8. Answer: 6322.

Question 7

Multiplying near a working base — beat the clock.

54 × 54 = ?

  1. 2900
  2. 2904
  3. 5816
  4. 2901
  5. 2916
Show the worked solution
  1. Deviations from 50: 54 → +4, 54 → +4.
  2. Cross-add for the raw left part: 54 + 4 = 58.
  3. Rescale for the working base: 50 is 100 ÷ 2, so divide by 2: 58 ÷ 2 = 29.
  4. Right part — multiply the deviations: (4) × (4) = 16, padded to two digits: 16.
  5. Join them: 29 | 16 → 2916.
  6. Answer: 2916.

Question 8

Squaring a number ending in 5 — beat the clock.

55² = ?

  1. 3019
  2. 3021
  3. 2525
  4. 3025
  5. 3023
Show the worked solution
  1. Ends in 5 — Ekadhikena: take 5, multiply by one more: 5 × 6 = 30.
  2. Append 25: 30 | 25 → 3025.
  3. Answer: 3025.

Question 9

Units sum to 10, same lead — beat the clock.

46 × 44 = ?

  1. 2030
  2. 2036
  3. 2034
  4. 1624
  5. 2024
Show the worked solution
  1. Units 6 + 4 = 10 with the same lead 4 — Antyayordashake applies.
  2. Left: 4 × 5 = 20. Right: 6 × 4 = 24 (always two digits).
  3. 20 | 24 → 2024.
  4. Answer: 2024.

Question 10

Multiply via the midpoint — beat the clock.

26 × 32 = ?

  1. 850
  2. 782
  3. 841
  4. 832
  5. 837
Show the worked solution
  1. 26 and 32 straddle 29 by 3 — Sankalana: a × b = m² − d².
  2. 29² − 3² = 841 − 9 = 832.
  3. Answer: 832.

Question 11

Nikhilam multiplication — beat the clock.

967 × 989 = ?

  1. 989967
  2. 363
  3. 956363
  4. 967989
  5. 1956000
Show the worked solution
  1. Choose the base (nearest power of 10): 1000.
  2. Distance from base: 967 is 33 below 1000, 989 is 11 below 1000.
  3. Cross-subtract: 967 − 11 = 956 (same as 989 − 33).
  4. Multiply the distances: 33 × 11 = 363.
  5. Base 1000 has 3 zeros, so the right-hand part must occupy exactly 3 digits.
  6. 363 fits, padded to 3 digits → 363.
  7. Left part: 956. Right part: 363.
  8. Write them side by side: 956 | 363 = 956363.

Question 12

Crosswise multiplication — beat the clock.

206 × 56 = ?

  1. 11536
  2. 10206
  3. 11236
  4. 11836
  5. 1536
Show the worked solution
  1. Urdhva builds one band per digit position, right to left — each band the SUM of its crosswise products.
  2. Units: 6×6 = 36. Tens: 0×6 + 6×5 = 30.
  3. Hundreds: 2×6 + 0×5 = 12. Thousands: 2×5 = 10.
  4. Stack with carries: 10000 + 1200 + 300 + 36 = 11536.
  5. Answer: 11536.

Question 13

Dividing by 11 — beat the clock.

999 ÷ 11 — what is the QUOTIENT?

  1. 78
  2. 98
  3. 90
  4. 79
  5. 80
Show the worked solution
  1. 999 ÷ 11 — Paravartya: 11 = 10 + 1, so the flag digit is 1; negate it to −1.
  2. Bring down the first digit as-is: 9 (first quotient digit).
  3. 9 + (−1 × 9) = 0 (next quotient digit).
  4. Last digit gives the remainder the same way: 9 + (−1 × 0) = 9.
  5. Quotient 90, remainder 9 — check: 90 × 11 + 9 = 999.
  6. Answer: 90.

Question 14

Multiplying near a working base — beat the clock.

48 × 48 = ?

  1. 2314
  2. 2305
  3. 4604
  4. 2304
  5. 9204
Show the worked solution
  1. Deviations from 50: 48 → −2, 48 → −2.
  2. Cross-add for the raw left part: 48 − 2 = 46.
  3. Rescale for the working base: 50 is 100 ÷ 2, so divide by 2: 46 ÷ 2 = 23.
  4. Right part — multiply the deviations: (-2) × (-2) = 4, padded to two digits: 04.
  5. Join them: 23 | 04 → 2304.
  6. Answer: 2304.
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Where these questions come from

Most free practice for this topic is a scanned upload or a blog quiz, and neither can tell you a question has exactly one answer. That is the one thing this set can promise: it is minted, not typed. The engine behind it serves ComputePrep's daily timed drill, so the questions here are the same shape as the ones a live round would give you — and there is an unlimited supply of them, which is why this page can be regenerated rather than padded.

If you want the method rather than more questions, Vedic multiplication: the crosswise sweep covers the approach, the traps and a worked table. This page and that one deliberately answer different questions: that one is how do I solve these, this one is give me vedic maths tricks questions with the answers.

FAQ

Which vedic technique is worth learning first?

Squaring numbers ending in five, then complementary products. Both are one-step rules that fire on sight, they cover a real share of exam arithmetic, and they pay back the ten minutes it takes to learn them within a single practice session.

Is vedic maths actually faster in an exam?

For the patterns it covers, substantially — a two-digit multiplication drops from about fifteen seconds to about four. It is not a general-purpose replacement for arithmetic. Learn to recognise the pattern first, because a technique applied to a number it does not fit is slower than the ordinary method.

What goes wrong most often with Nikhilam multiplication?

The carry. When the product of the two deviations exceeds the base's digit count, the excess carries into the left half, and skipping that step produces a number that looks right and is off by a hundred. The wrong options on these questions are built from exactly that slip.

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